As promised
Technothlon team is back to take the discussion further, and to more core
sections. The discussion for the section, 'INGENIOSO MATEMATICA' will be on for
another 2 days. There's a lot to gain from these questions. Hope to see you all
commenting with your strategies, and a few shortcuts you might have
discovered accidentally during the prelims.
"Juniors"
Q-1:
In
the botanical garden owned by Vijay, there are three type of plants; ones which
bear red flowers (I), ones which bear pink flowers (II), and rest bear both
(III). Currently, the garden accommodates equal number of flowers from each
category. As an effect of fertilizers, the red ones have lost their ability to reproduce
and the rest two have equal chance to reproduce any of the three types, but one
plant can reproduce only one plant at a time. The moment type-III plant is
produced; the mother plant is treated so as to stop reproducing. If this
continues for a long time, what would be the average number of child plants,
that a mother plant ( type II and III) would have?
1) 1 2)
3 3)
2 4)
6
Q-2:
Kanheiya
has joined the summer camp, where he gets to solve some interesting problems to
sharpen his brain. He has been given 2 cubes, using which he has to represent
all the months and dates. Each
face of a cube bears different digits (from 0-9), but the digits on the two
cubes can be the same. He does that first assuming that ‘5’ will be represented
as ‘5’ and not ‘05’. He then repeats the same for the case where ‘5’ is
represented as ‘05’. What’s the minimum number of common faces the two cubes
can have, with first cube faces adding up to give the least sum, in the two
cases.
1) 2,2 2)
2,3 3)
3,3 4)
3,2
Q-3:
Megha
has been selected as the Event Organizer for the upcoming Rangoli Competition
in your society and has to buy 100 colour packets, using only the society fund
of Rs. 100. She decides to spend
all the fund for buying colours only. A red colour packet costs Rs. 6 each, a
yellow one Rs. 3 and Green one for Rs 0.10. How many colour packets will she
have?
(How to answer? If
Megha bought 15 Red packets, 50 Yellow packets, and 35 Green packets then your answer should
be: 5035 i.e. first two digits will be the number of yellow packets and the
last two digits will be
the number of green packets.)
Q-4:
Sanny is trying to label two wires with their capacity, which is the
maximum weight it can handle. He knows that the capacity of both the wires is
the same and is between 1 and 100 kg. He has 100 weights: 1kg, 2kg, 3kg, ….,
100kg, to test the capacity. What is the least number of trials required by
Sanny for knowing the capacity?
(How to answer? If he takes
123 trials, then answer 0123.)
Q-5:
Eight shopkeepers, who used to quarrel a lot among themselves, were
given slot numbers by a fair owner as 1 to 8, such that the shopkeeper with a
particular number will have his quarreling mates as his nearest numbers. The
shops are separated by the roads as shown below. Now it’s the time to arrange
their shops for the fair on the map such that no one will encounter his
quarreling mate just next, in a row or a column or diagonally.
Sayantan,
the owner has done it, can you?
(How to answer? Give the
unit’s digit of all the three columns in the increasing order. Eg: if the three
sums (left to right) are: 99,98,97, (which surely can’t be!) then the answer
is: 0789.)
"Hauts"
Q-6:
There are 8 teams in a tournament, and are known by their
captains names. Four matches will take place to select the teams for the next
level. Every team plays only once. Three umpires have predicted the following
winners, and see the coincidence, all three of them are correct.
Umpire-1:
Sayantan, Vijay, Ashima, and Vishal.
Umpire-2:
Kanheiya, Himanshu, Ashima, and Sayantan.
Umpire-3:
Anirudh, Vijay, Himanshu, and Sayantan.
None
picked Greeshma. Who played with Kanheiya?
1)
Anirudh 2) Vijay 3) Vishal 4) none of these
Q-7:
A lunar Spaceship takes off every odd hour
(1,3,5,7,...), night and day, from the Piternia launching station. Every odd
hour a ship, from the moon also leaves for earth. A constant distance is
maintained from one another by the spaceships, in both directions , and the
speed is maintained so that they arrive at the final spot on the even
hour(2,4,6,8,...). You are lucky to get a chance to go in the space shuttle,
with your partner. “That’s the seventh ship we’ve passed since we left the
ground.”,says the person seated by the window.
On
which ship are you riding?
1)
E 2) C 3) D 4) G
Q-8:
Kushal has joined the summer camp, where he gets to solve
some interesting problems to sharpen his brain. He has been given 2 cubes,
using which he has to represent all the months and
dates. Each face of a cube bears a unique digit(from 0-9), but the digits on
two cubes can be
same. He does that first assuming that ‘5’ will be represented as ‘5’ and not ‘05’.
He then repeats
the same for the case where ‘5’ is represented as ’05’. What’s the minimum
number of common
faces the two cubes can have, with first cube faces adding up to give the least
sum, in 2
cases.
Q-9:
A long time ago, when the Egyptian Empire was spreading across
the boundaries of Egypt; several different ethnic groups were made slaves. Over
time the slave communities united and made their own Pidgin(a new language) to
communicate with each other. To take revenge, the oldest members of these
groups: Dhruv, Sanny, and Zilani, indulged in black magic, and cursed the
oldest and the most powerful Mummy of the Dynasty and its treasure: “WARTS AKA
STRAW” meaning: “2013 will see the fall of Dynasty and you would be the reason”.
But the curse will show its effect only when the Mummy is re-awaken, and the
one who reawakens will die. To save the Empire one must get control over the
Mummy.
Now in 2013 A.D., archeologists Anirudh and Vishal visit
the pyramids in search of the treasure, and come across a manuscript which asks
them to find the number of ways there are, to spell, “WARTS AKA STRAW” excluding
the spaces, by travelling from letter to letter in the grid. Unaware of the
curse, in greed
of
Treasure they accidently re-awake the Mummy, and are forced to death. You can
save the Empire by getting control over the Mummy if you can find this
mysterious number.
(Hint:
Most probably, much more than you think.)
(Hint:
Every possible path passes through the center.)
(How to answer? Answer the last four digits of your answer. Eg.: if the answer is:
0123, then mark your answer as: 0123 .)
Q-10:
In a botanical garden, owned by Megha; there are three
types of plants, ones which bear red flowers (I), ones which bear pink flowers
(II), and rest bear both (III). Currently, the garden accommodates equal number
of flowers from each category. As an effect of fertilizers, the red ones have
lost the ability to reproduce, and the rest two have equal chances to reproduce
any of the three types, but one plant can reproduce only one plant at a time.
The moment type-III plant is produced; the mother plant is treated so as to stop
reproducing. If this continues for a long time, what would be the ratio of the
three types of plants in the garden?
(How to answer? If the ratio is: x:y:z (say 7:8:9) then answer xyz(0789) .)
Q no 6 - (2)vijay
ReplyDelete7- (3)D
8- three
9- 9999 means uncountable
ans 9) should be wrong as it is countable
DeleteJUNIOR SQUAD PAPER ANSWERS.
ReplyDeleteA.11 (D)6
A.12(D)3,2
A.13 - 2970(THERE ARE 29 YELLOW PACKETS,70 GREEN PACKETS AND 1 RED PACKET.TOTAL PACKETS-100.TOTAL COST-100)
A.14 - 0049(MINIMUM NO.OF TRIALS = NO.OF OBSERVATION/2)
A.15 -0880)INCREASING ORDER OF NO.S FROM LEFT TO RIGHT.HERE IN CREASING ORDER MEANS FROM DIRECTION NOT MAGNITUDE.)
Amartya, dear can you please explain solution of ques. No. 15?
DeleteJUNIOR SQUAD
ReplyDelete1. 3)2
2. 2)2,3
3. 2970
4. 0011
5. 0088
how do u got the fourth one??
Deletefirst answer should be 2)3
Delete@amartya for increasing order we will right the answer as 0088 not 0880 as 8>0
ReplyDeletecan anyone explain the first 2 mcq of this section
ReplyDeleteAns 6 : 2) Vijay
ReplyDeleteSolution : The teams are as follows :- sanyantam - Greeshma, vijay - kanheiya , ashima - anirudh, vishal - himanshu
Ans 7 : 3) D
Solution : Each spaceship has to cross 8 steps to reach destination.
G passes 1st ship when it crosses 4th position. so in its total journey it passes 4 ships. F passes 1 more ship than G i.e 5. E passes 6 and D passes 7!!
Ans 9 : 3111696
Solution :
1) divide the kite in 4 parts along the diagonals
2) the word can be formed by combining half of it from one Quadrant and the other from other quadrant
3) let us consider the upper left part -
To obtain that word 1st chose any 'w' if it is the corner one then you have only one choice to chose 'a' (i.e. the one immediately next to it). If it is not the corner one you have two choices for 'a' (either below or to the right).
3) likewise when you reach a letter you have two choices for the next letter ( right or below) except the letters on the diagonal (which have just 1)and 'k' which has 0.
4) so you can construct half of that word by adding the total number of choices (12 + 2*15 = 42)
5) and for the complete word you will have to multiply choices from every Quadrant. (42*42*42*42 = 3111696)
JUNIOR SQUAD
ReplyDelete1. 3)2
2. 2)2,3
3. 2970
4. 0011
5. 0088
4. It is 0007
ReplyDeletebecause first we will check with 50 if it is greater or smaller. Let us assume that it is greater than 50. Then we wiol check with 75. Then ideally we have to check with 87.5 but we will check with the round off 88. Then we'll ideall check with 93.75 but roundoff 94. Then ideally we will check with 96.875 but roundoff 97 and so on till the difference between two ideal measures is less than one.i.e. 7
Junior Squads
Delete1. 2) 3
2. 3)3, 3
3. 2970
4. 1960
5. 0088
sorry it is 0011 because
Deletex + (x-1) + (x-2) + (x-3) + ... + 1
x(x+1)/2 = 100
so we can say that
TRIALS
#0 14
#1 27
#2 39
#3 50
#4 60
#5 69
#6 77
#7 84
#8 90
#9 95
#10 99
#11 100
SINCE we have 100 marbles the answer is 11
x + (x-1) + (x-2) + (x-3) + ... + 1
ReplyDeletex(x+1)/2 = 100
so we can say that
TRIALS
#0 14
#1 27
#2 39
#3 50
#4 60
#5 69
#6 77
#7 84
#8 90
#9 95
#10 99
#11 100
SINCE we have 100 marbles the answer is 11
Reply
Q4 of junior] answer should be 14
ReplyDelete1st try 14 kg on 1st wire.
if the wire breaks try 1 to 13 on second wire.suppose the 2nd wire doesn't break on 6kg, breaks on 7 kg. it can handle max 6 kg.total 14 trials may be required
if 1st wire dose not break on 14 kg try 27 kg.
if it breaks. try 15kg to 26 kg to find from what mass it starts breaking.total 14 trials may be required.
if 1st wire dose not break on 27 kg try 39 kg.
continue in a similar manner.
would we ever get answers to this section and then to strategia
ReplyDeleteJunior squad-
ReplyDeleteQ.1- 4) 60
Q3) 2970
Q4) 0007
Q5) 0088
could not view the result!! Technothlon does not have it in there database!! Can some body help??
ReplyDelete